A Continuous and Aligned Fiber reinforced Composite is to Be Produced Consisting of
A continuous and aligned fiber-reinforced composite is to be produced consisting of 30 vol% aramid fibers and 70 vol% of a polyc
arbonate matrix; mechanical characteristics of these two materials are as follows:
Modulus of Elasticity [GPa] Tensile Strength [MPa] Aramid fiber 131 3600 Polycarbonate 2.4 65
Also, the stress on the polycarbonate matrix when the aramid fibers fail is 45 MPa. For this composite, compute the following:
(a) the longitudinal tensile strength, and
(b) the longitudinal modulus of elasticity
1 answer:
Answer:
1. 1111.5MPa
2. 56.1GPa
Explanation:
1. Longitudinal tensile stress can be obtained by obtaining the strength and volume of the fiber reinforcement. The derived formula is given by;
σcl = σm (1 - Vf) + σfVf
Substituting the figures, we will have;
45(1 - 0.30) + 3600(0.30)
45(0.70) + 1080
31.5 + 1080
= 1111.5MPa
2. Longitudinal modulus of elasticity or Young's modulus is the ability of an object to resist deformation. The derived formula is given by;
Ecl = EmVm + EfVf
Substituting the formula gives;
= 2.4 (1 - 0.30) + 131 (0.30)
= 2.4(0.70) + 39.3
= 16.8 + 39.3
= 56.1GPa
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Explanation:
If we neglect the absorption of heat of the excess of oxygen because is low compared with the calorimeter, then we can assume that all the heat released by the reaction Q gra is absorbed by the calorimeter Q cal ( if we assume also that the calorimeter is completely isolated). Then
Q gra + Q cal = Q surr =0
since
- Q gra = ΔU ( constant volume process)
- Q cal = C * (T final - T initial ) , where C= heat capacity of the calorimeter, T final = final temperature of the calorimeter , T initial = initial temperature o the calorimeter,
ΔU + C*(T final - T initial ) = 0 → ΔU = C* (T initial - T final )
but the relationship between constant volume heat ( ΔU) and constant pressure heat ( ΔH = heat of reaction) is
ΔH = ΔU + R*T*Δn
where Δn= variation of moles of gas due to the reaction .
Since the oxygen is in excess we assume that all the graphite will react and turn into carbon dioxide
C + O₂ → CO₂ , but since the stoichiometric coefficients are the same Δn=0 ( one mole of O₂ consumed generates one mole of CO₂ , thus there is no variation in the number of moles of gas)
therefore
ΔH = ΔU = C* (T initial - T final ) = 20.7 kJ/˚C* (25.00˚C - 25.89˚C ) = -18.423 kJ
or the specific heat of reaction
Δh= ΔH/m = 18.423 kJ/ 0.562 gr * 12gr/mol = 393.37 kJ/mol of graphite
Answer:
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Explanation:
Answer:
pin punch
Explanation:
- <em><u>Pin</u></em> <em><u> </u></em> <em><u>Punch</u></em> <em><u> </u></em>
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Answer:
AC or
Explanation:
BC
Answer:
i) when circuit is unloaded : R1 + R2 = 2kΩ.
ii) when 5V output voltage is applied : R1 = 1 kΩ , R2 = 1 kΩ
iii) when 2.5 v output voltage is applied : R1 = 1500 Ω, R2 = 500 Ω
iv) when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V
When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V
Explanation:
Current drawn from source under loaded condition ≤ 5 mA
source voltage = 10 v , required output = 5 v , 2.5 v
attached below is the sketch of the circuit
Resistance values
<em>i) when the circuit is unloaded </em>
Req = R1 + R2 = 2 kΩ ( Req = Vs / I = 10 / 5*10^-3 = 2 kΩ )
<em>ii) when output voltage = 5 v</em>
we will apply voltage divider rule
R1 = 1 kΩ ,
R2 = 1 kΩ
<em>iii) When the output voltage = 2.5 v </em>
applying voltage divider rule
R1 = 1500 Ω
R2 = 500 Ω
iv) when the load is connected to each tap one at a time
i.e. when the resistance are in parallel
when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V
When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V
attached below is the detailed solution to the given problem
charbonneauanscialtat.blogspot.com
Source: https://1answer.guru/questions/7017132-a-continuous-and-aligned-fiber-reinforced-composite-is-to-be.html
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